.88x^2+1.9x+1=0

Solution for .88x^2+1.9x+1=0 equation:

.88x^2+1.9x+1=0

a = .88; b = 1.9; c = +1;
Δ = b2-4ac
Δ = 1.92-4·.88·1
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.9)-\sqrt{0.09}}{2*.88}=\frac{-1.9-\sqrt{0.09}}{1.76}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.9)+\sqrt{0.09}}{2*.88}=\frac{-1.9+\sqrt{0.09}}{1.76}
$